In the following reaction,the major product w | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The given reaction is the Hunsdiecker reaction,which involves the treatment of a silver salt of a carboxylic acid with bromine in the presence of

Vedclass · Accepted Answer

$C_6H_5-CH_2-Br$

Vedclass · Answer

(B) The given reaction is the Hunsdiecker reaction,which involves the treatment of a silver salt of a carboxylic acid with bromine in the presence of carbon tetrachloride $(CCl_4)$ under reflux conditions.In this reaction,the carboxylate group $(-COOAg)$ is replaced by a bromine atom,resulting in the loss of $CO_2$ and the formation of an alkyl bromide with one carbon atom less than the original carboxylic acid.The reaction is: $C_6H_5-CH_2-COOAg + Br_2 \xrightarrow{CCl_4, \Delta} C_6H_5-CH_2-Br + CO_2 + AgBr$.Therefore,the major product is benzyl bromide $(C_6H_5-CH_2-Br)$.

List-$I$	List-$II$
$(A)$ Sandmeyer reaction	$(I)$ $R-I$
$(B)$ Finkelstein reaction	$(II)$ $R-F$
$(C)$ Swarts reaction	$(III)$ $Ar-Br$
	$(IV)$ $R-Br$

In the following reaction,the major product will be:

Similar Questions

Benzyl chloride $(C_6H_5CH_2Cl)$ is prepared from toluene by chlorination with ................?

The alkyl halides required to prepare $2,3-$dimethylbutane by the Wurtz reaction are

Alkyl halides can be obtained by all methods except:

The product obtained when ethyl alcohol is distilled with bleaching powder is

Match the following reactions in List-$I$ with the products obtained in List-$II$:
List-$I$ List-$II$
$(A)$ Sandmeyer reaction $(I)$ $R-I$
$(B)$ Finkelstein reaction $(II)$ $R-F$
$(C)$ Swarts reaction $(III)$ $Ar-Br$
$(IV)$ $R-Br$

Vedclass Test Series

Exam Paper Generator

Online Exam Module