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(B) In a face-centred cubic $(FCC)$ unit cell,there are $8$ corners and $6$ face centres.Each corner atom contributes $1/8$ to the unit cell.The total

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Each cube diagonal

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(B) In a face-centred cubic $(FCC)$ unit cell,there are $8$ corners and $6$ face centres.Each corner atom contributes $1/8$ to the unit cell.The total number of atoms per unit cell is $Z = (8 	imes 1/8) + (6 	imes 1/2) = 4$.The number of tetrahedral voids is equal to $2Z$,which equals $2 	imes 4 = 8$.These $8$ tetrahedral voids are located on the body diagonals of the cube,at a distance of $1/4$ of the body diagonal length from each corner.

In a face-centred cubic $(FCC)$ lattice,where are the tetrahedral voids located?

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