In equimolar solutions of glucose,NaCl,and Ba | vedclass

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Question

(C) Osmotic pressure $(\pi)$ is a colligative property,which depends on the number of particles in the solution. The formula is $\pi = iCRT$,where $i$

Vedclass · Accepted Answer

$BaCl_2 > NaCl >$ Glucose

Vedclass · Answer

(C) Osmotic pressure $(\pi)$ is a colligative property,which depends on the number of particles in the solution. The formula is $\pi = iCRT$,where $i$ is the van't Hoff factor.For glucose,it is a non-electrolyte,so $i = 1$.For $NaCl$,it dissociates as $NaCl \rightarrow Na^+ + Cl^-$,so $i = 2$.For $BaCl_2$,it dissociates as $BaCl_2 \rightarrow Ba^{2+} + 2Cl^-$,so $i = 3$.Since the solutions are equimolar ($C$ is constant),the osmotic pressure depends directly on $i$. Therefore,the order is $BaCl_2 (i=3) > NaCl (i=2) >$ Glucose $(i=1)$.

In equimolar solutions of glucose,$NaCl$,and $BaCl_2$,the order of osmotic pressure is as follows:

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