In Dumas method,$0.3 \ g$ of an organic compound gave $45 \ mL$ of nitrogen at $STP$. The percentage of nitrogen is

$0.259 \ g$ of an organic compound gives $0.350 \ g$ of $BaSO_4$ upon treatment. Calculate the percentage of sulphur in the compound. (Atomic masses: $Ba = 137, S = 32, O = 16$) (in $\%$)

The transformation occurring in Dumas's method is given below:
$C_{2}H_{7}N + (2x + \frac{y}{2})CuO \rightarrow xCO_{2} + \frac{y}{2}H_{2}O + \frac{z}{2}N_{2} + (2x + \frac{y}{2})Cu$
The value of $y$ is ...... .(Integer answer)

Differentiate between the principle of estimation of nitrogen in an organic compound by $(i)$ Dumas method and $(ii)$ Kjeldahl's method.

Differentiate between the principle of estimation of nitrogen in an organic compound by $(i)$ Dumas method and $(ii)$ Kjeldahl's method.

$0.16 \ g$ of an organic compound containing sulphur produces $0.233 \ g$ of $BaSO_4$. The percentage of sulphur in the compound is: