In Drosophila, the allele for a normal grey b | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) To determine the genotype of the strains, we analyze the test cross results:$1.$ Strain $1 	imes gg$ results in all wild type $(G-)$. This indica

Vedclass · Accepted Answer

$II$ and $IV$

Vedclass · Answer

(D) To determine the genotype of the strains, we analyze the test cross results:$1.$ Strain $1 	imes gg$ results in all wild type $(G-)$. This indicates Strain $1$ must be homozygous dominant $(GG)$.$2.$ Strain $2 	imes gg$ results in $1$ wild type $(Gg)$ $: 1$ ebony $(gg)$. This is a test cross, indicating Strain $2$ is heterozygous $(Gg)$.$3.$ Strain $3 	imes gg$ results in all ebony $(gg)$. This indicates Strain $3$ must be homozygous recessive $(gg)$.$4.$ Strain $4 	imes Gg$ results in $3$ wild type $: 1$ ebony. This is a monohybrid cross between two heterozygotes $(Gg 	imes Gg)$, indicating Strain $4$ is heterozygous $(Gg)$.Therefore, both Strain $2$ and Strain $4$ have the genotype $Gg$.

$S.No$	Cross	Result
$I.$ Strain $1 \times gg$	All wild type
$II.$ Strain $2 \times gg$	$1$ wild type $: 1$ ebony
$III.$ Strain $3 \times gg$	All ebony
$IV.$ Strain $4 \times Gg$	$3$ wild type $: 1$ ebony

Similar Questions

$A$ tobacco plant which is heterozygous for albinism ($a$ recessive character) is self-pollinated. If $1200$ seeds are subsequently germinated,how many of the seedlings would have the parental genotype?

$A$ cross between two homozygous parents that differ in only one gene locus is known as a....

Explain the Law of Dominance using a monohybrid cross.

Show the phenotypic and genotypic ratios obtained from a Punnett square for a monohybrid cross.

In a plant,black seed color $(BB / Bb)$ is dominant over white seed color $(bb)$. In order to find out the genotype of the black seed plant,with which of the following genotype will you cross it?

Vedclass Test Series

Exam Paper Generator

Online Exam Module