If the mass and the acceleration of an object are both doubled,how does the force acting on the object change with respect to its previous value?

$A$ constant force acts on a body of mass $0.9 \,kg$ at rest for $10 \,s$. If the body moves a distance of $250 \,m$,the magnitude of the force is.........$N$

$A$ body of mass $1 \, kg$ is acted upon by a force $\vec F = 2\sin(3\pi t)\hat i + 3\cos(3\pi t)\hat j$. Find its position at $t = 1 \, s$ if at $t = 0$ it is at rest at the origin.

The momentum $p$ (in $kg \cdot m/s$) of a particle is varying with time $t$ (in $s$) as $p = 2 + 3t^2$. The force acting on the particle at $t = 3 \, s$ will be ......... $N$.

$A$ body of mass $1.5 \ kg$ is moving towards south with a uniform velocity of $8 \ ms^{-1}$. $A$ force of $6 \ N$ is applied to the body towards east. The displacement of the body $3 \ s$ after the application of the force is (in $m$)

$5\, kg$ દળ ધરાવતા એક પદાર્થ પર અચળ બળ $\overrightarrow F = {F_x}\hat i + {F_y}\hat j$ લાગે છે. $t = 0\, s$ સમયે તેનો વેગ $\overrightarrow v = (6\hat i - 2\hat j)\, m/s$ છે અને $t = 10\, s$ સમયે તેનો વેગ $\overrightarrow v = 6\hat j\, m/s$ છે. તો બળ $\overrightarrow F$ શોધો.