In dealing with motion of projectile in air, we ignore effect of air resistance on motion. This give trajectory as a parabola as you have studied. What would the trajectory look like if air resistance is include ? Sketch such a trajectory and explain why you have drawn it that way.
Due to air resistance, energy and velocity of particle keep on decreasing making the fall steeper shown in the figure.
When we neglect air resistance path is symmetric parabola $(OAB)$. When air resistance is considered path is asymmetric parabola $(OAC).$
A water fountain on the ground sprinkles water all around it. If the speed of water coming out of the fountain is $v$, the total area around the fountain that gets wet is :
The horizontal range is four times the maximum height attained by a projectile. The angle of projection is .......... $^o$
If $R$ and $H$ are the horizontal range and maximum height attained by a projectile, than its speed of projection is ..........
A particle is projected from ground at an angle $\theta$ with horizontal with speed $u$. The ratio of radius of curvature of its trajectory at point of projection to radius of curvature at maximum height is ........
The maximum height attained by a projectile is increased by $10\,\%$ by increasing its speed of projection, without changing the angle of projection. The percentage increases in the horizontal range will be $...........\,\%$