In chrysoberyl,a compound containing berylliu | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Let the number of oxide ions $(O^{2-})$ in the $ccp$ structure be $N$.Number of octahedral voids = $N$.Number of tetrahedral voids = $2N$.Given th

Vedclass · Accepted Answer

$BeAlO_{4}$

Vedclass · Answer

(A) Let the number of oxide ions $(O^{2-})$ in the $ccp$ structure be $N$.Number of octahedral voids = $N$.Number of tetrahedral voids = $2N$.Given that $Al^{3+}$ ions occupy $\frac{1}{4}$ of the octahedral voids,so number of $Al^{3+} = \frac{1}{4} 	imes N = \frac{N}{4}$.Given that $Be^{2+}$ ions occupy $\frac{1}{8}$ of the tetrahedral voids,so number of $Be^{2+} = \frac{1}{8} 	imes 2N = \frac{N}{4}$.The ratio of $Be : Al : O$ is $\frac{N}{4} : \frac{N}{4} : N$.Multiplying by $4$,we get the ratio $1 : 1 : 4$.Therefore,the formula of the compound is $BeAlO_{4}$.

In chrysoberyl,a compound containing beryllium,aluminium and oxygen,oxide ions form a cubic close-packed structure. Aluminium ions occupy $\frac{1}{4}$ of the octahedral voids and beryllium ions occupy $\frac{1}{8}$ of the tetrahedral voids. The formula of the compound is

Similar Questions

Calculate the volume occupied by all atoms in a $bcc$ unit cell if the volume of the unit cell is $1.5 \times 10^{-22} \ cm^3$.

Atoms of element $B$ form $hcp$ lattice and those of the element $A$ occupy $2/3$ of tetrahedral voids. What is the formula of the compound formed by the elements $A$ and $B$?

Explain the Hexagonal Close Packing $(hcp)$ and Cubic Close Packing $(ccp)$ or Face-Centered Cubic $(fcc)$ structures.

An ionic solid is $HCP$ of $B^{2-}$ ions and $A^{x+}$ ions are in one-fourth of tetrahedral voids. The value of $x$ should be

$A$ compound is formed by elements $A$ and $B$. Element $B$ forms an $HCP$ lattice,and element $A$ occupies $2/3$ of the tetrahedral voids. What is the formula of the compound formed by $A$ and $B$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module