In Carius method of estimation of halogens,$250 \ mg$ of an organic compound gave $141 \ mg$ of $AgBr$. The percentage of bromine in the compound is:

Explain the Carius method and its principle for the estimation of halogen elements.

On complete combustion,$0.246 \ g$ of an organic compound gave $0.198 \ g$ of carbon dioxide and $0.1014 \ g$ of water. Determine the percentage composition of carbon and hydrogen in the compound.

What is the reason for passing dry air through the combustion tube during the estimation of $C$ and $H$?

In sulphur estimation,$2.0 \times 10^{-3}$ mol of an organic compound $(X)$ (molar mass $76 \text{ g mol}^{-1}$) gave $0.4813 \text{ g}$ of barium sulphate (molar mass $233 \text{ g mol}^{-1}$). The percentage of sulphur in the compound $(X)$ is . . . . . . $\% \times 10^{-1}$ (Nearest integer).

In the estimation of bromine,$0.5 \ g$ of an organic compound gave $0.40 \ g$ of silver bromide. The percentage of bromine in the given compound is $..... \ \%$ (nearest integer).
(Relative atomic masses of $Ag$ and $Br$ are $108 \ u$ and $80 \ u$,respectively).