In Calvin cycle,......... ATP and ......... N | vedclass

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(A) To synthesize one molecule of glucose $(C_6H_{12}O_6)$ in the Calvin cycle,$6$ turns of the cycle are required.Each turn of the Calvin cycle consu

Vedclass · Accepted Answer

$72 \, ATP, 48 \, NADPH, 24$ times

Vedclass · Answer

(A) To synthesize one molecule of glucose $(C_6H_{12}O_6)$ in the Calvin cycle,$6$ turns of the cycle are required.Each turn of the Calvin cycle consumes $3 \, ATP$ and $2 \, NADPH$ molecules.Therefore,for $1$ molecule of glucose:$ATP$ required = $6 	imes 3 = 18 \, ATP$$NADPH$ required = $6 	imes 2 = 12 \, NADPH$For $4$ molecules of glucose:$ATP$ required = $4 	imes 18 = 72 \, ATP$$NADPH$ required = $4 	imes 12 = 48 \, NADPH$Total turns required = $4 	imes 6 = 24$ times.Thus,the correct requirement is $72 \, ATP, 48 \, NADPH$ and $24$ turns.

In Calvin cycle,......... $ATP$ and ......... $NADPH$ are required for the formation of four molecules of glucose,and the cycle turns for ......... times.

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