In Bohr's model of hydrogen-like species,whic | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The kinetic energy $(KE)$ of an electron in the $n$-th orbit of a hydrogen-like species with atomic number $Z$ is given by $KE = 13.6 	imes \frac

Vedclass · Accepted Answer

$KE$ of electron in ground state of hydrogen atom is equal to $KE$ of electron in $n = 3$ state of $Li^{2+}$

Vedclass · Answer

(A) The kinetic energy $(KE)$ of an electron in the $n$-th orbit of a hydrogen-like species with atomic number $Z$ is given by $KE = 13.6 	imes \frac{Z^2}{n^2} 	ext{ eV}$.For hydrogen atom $(Z=1)$,$KE$ in ground state $(n=1)$ is $13.6 	imes \frac{1^2}{1^2} = 13.6 	ext{ eV}$.For $Li^{2+}$ $(Z=3)$,$KE$ in $n=3$ state is $13.6 	imes \frac{3^2}{3^2} = 13.6 	ext{ eV}$.Comparing these,the $KE$ of an electron in the ground state of a hydrogen atom is equal to the $KE$ of an electron in the $n=3$ state of $Li^{2+}$.Thus,option $A$ is correct.

In Bohr's model of hydrogen-like species,which of the following is true?

Similar Questions

An electron makes a transition from orbit $n = 4$ to the orbit $n = 2$ of a hydrogen atom. The wave number of the emitted radiations ($R =$ Rydberg's constant) will be

In a hydrogen atom,an electron excites from the ground state to a higher energy state,and its orbital velocity is reduced to $\frac{1}{3}$ of its initial value. The radius of the orbit in the ground state is $R$. The radius of the orbit in that higher energy state is: (in $R$)

Magnetic moment due to the motion of the electron in the $n$th energy state of a hydrogen atom is proportional to ..........

The angular momentum of an electron in the $2^{nd}$ excited state of a Helium ion $(He^+)$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module