In benzene molecule all $C - C$ bond lengths are equal because
All carbon atoms are equivalent
All carbon atoms are $s{p^2}$ hybridised
All $C - C$ bonds in benzene, have same order
All $C - C$ bonds are single covalent bond
All the $( \mathrm{C -O} )$ bonds in carbonate ion $\left( {{\rm{CO}}_3^{2 - }} \right)$ are equal in length. - Explain.
How many resonance forms can be written for the nitrate ion, $(NO^-_3)$ ?
Resonance hybrid of nitrate ion is
The species having no $p \pi - p \pi$ bond but has bond order equal to that of $O_2$