In an argon atom,how many electrons have m_{e | vedclass

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(A) The electronic configuration of argon $(Z = 18)$ is $1s^2, 2s^2, 2p^6, 3s^2, 3p^6$.For $p$-orbitals,the azimuthal quantum number $l = 1$,so the ma

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$4$

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(A) The electronic configuration of argon $(Z = 18)$ is $1s^2, 2s^2, 2p^6, 3s^2, 3p^6$.For $p$-orbitals,the azimuthal quantum number $l = 1$,so the magnetic quantum number $m_{\ell}$ can take values $-1, 0, +1$.In the $2p^6$ subshell,there are $2$ electrons in the $2p_x$ orbital (where $m_{\ell} = 1$ or $-1$ depending on convention).In the $3p^6$ subshell,there are also $2$ electrons in the $3p_x$ orbital (where $m_{\ell} = 1$ or $-1$ depending on convention).Thus,the total number of electrons with $m_{\ell} = 1$ is $2 + 2 = 4$.

In an argon atom,how many electrons have $m_{\ell} = 1$?

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