In aqueous solution,glucose remains as:

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(D) In an aqueous solution,glucose exists in a dynamic equilibrium between its open-chain form and two cyclic (pyranose) forms,known as $\alpha-D-(+)-

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In all three forms in equilibrium

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(D) In an aqueous solution,glucose exists in a dynamic equilibrium between its open-chain form and two cyclic (pyranose) forms,known as $\alpha-D-(+)-glucopyranose$ and $\beta-D-(+)-glucopyranose$. The equilibrium mixture consists of approximately $36\%$ of $\alpha$-anomer,$64\%$ of $\beta$-anomer,and a very small amount (about $0.02\%$) of the open-chain form. Therefore,glucose exists in all three forms in equilibrium.

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Assertion : Treatment of $D$-glucose with dilute alkali affords an equilibrium mixture consisting of $D$-mannose,$D$-fructose and starting substance $D$-glucose.
Reason : The reaction involves an intermediate in which hybridization of $C_2$ changes from $sp^3$ to $sp^2$.

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