In an open-end organ pipe of length L,if the | vedclass

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(A) For an open organ pipe of length $L$,the boundary conditions require antinodes at both open ends.The fundamental mode (first harmonic) corresponds

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$\frac{V}{2L}$ and all harmonics are present.

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(A) For an open organ pipe of length $L$,the boundary conditions require antinodes at both open ends.The fundamental mode (first harmonic) corresponds to the condition where the length of the pipe $L$ is equal to half the wavelength,i.e.,$L = \frac{\lambda}{2}$,so $\lambda = 2L$.Using the wave equation $V = f \lambda$,the fundamental frequency $f$ is given by $f = \frac{V}{\lambda} = \frac{V}{2L}$.In an open organ pipe,all harmonics (integer multiples of the fundamental frequency) are present,meaning both odd and even harmonics are produced.

In an open-end organ pipe of length $L$,if the velocity of sound is $V$,then the fundamental frequency will be (Neglect end correction).

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