In an explosion,a body breaks up into two pie | vedclass

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(A) According to the law of conservation of linear momentum,if no external force acts on the system,the total momentum remains constant.Initially,the

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Both parts will have numerically equal momentum

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(A) According to the law of conservation of linear momentum,if no external force acts on the system,the total momentum remains constant.Initially,the body is at rest,so the initial momentum is $P_{initial} = 0$.After the explosion,if the two pieces have masses $m_1$ and $m_2$ and velocities $v_1$ and $v_2$ respectively,then $m_1 v_1 + m_2 v_2 = 0$.This implies $m_1 v_1 = -m_2 v_2$.Taking the magnitude,$|p_1| = |p_2|$.Thus,both parts will have numerically equal momentum,but in opposite directions.

In an explosion,a body breaks up into two pieces of unequal masses. In this process:

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