In an experiment to study the photoelectric effect,the observed variation of stopping potential $(V_0)$ with the frequency $(
u)$ of incident radiation is as shown in the figure. The slope and $y$-intercept are respectively

In the case of the photoelectric effect, on increasing the frequency of incident light:

The beam of light has three wavelengths $4144 \,\mathring A$,$4972 \,\mathring A$,and $6216 \,\mathring A$ with a total intensity of $3.6 \times 10^{-5} \, W/m^2$ equally distributed amongst the three wavelengths. The beam falls normally on an area of $1 \, cm^2$ of a clean metallic surface with a work function of $2.3 \, eV$. Assume that there is no loss of light by reflection and that each energetically capable photon ejects one electron. Calculate the number of photoelectrons liberated in $2 \, s$.

Assuming photoemission to take place,the factor by which the maximum velocity of the emitted photoelectrons changes when the wavelength of the incident radiation is increased four times,is

When light of frequency $v_{1}$ is incident on a metal with work function $W$ (where $h v_{1} > W$),then the photocurrent falls to zero at a stopping potential of $V_{1}$. If the frequency of light is increased to $v_{2}$,the stopping potential changes to $V_{2}$. Therefore,the charge of an electron $e$ is given by:

Light of wavelength $488 \, nm$ produced by an Argon laser is used in the photoelectric effect. When light from this spectral line is incident on the cathode, the stopping potential of the photoelectrons is $0.38 \, V$. The work function of the cathode material is (in $ \, eV$)