In an examination,the maximum marks for each of three subjects is $n$ and that for the fourth subject is $2n$. The number of ways in which a candidate can get $3n$ marks is

  • A
    $\frac{1}{6}(n+1)^2(5n^2+10n+6)^2$
  • B
    $\frac{1}{6}(n+1)(5n^2+10n+6)^2$
  • C
    $\frac{1}{6}(n+1)^2(5n^2+10n+6)$
  • D
    $\frac{1}{6}(n+1)(5n^2+10n+6)$

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