In an examination,30 % and 35 % students resp | vedclass

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(B) Let $H$ be the set of students who failed in History and $G$ be the set of students who failed in Geography.Given: $n(H) = 30 \%$,$n(G) = 35 \%$,a

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$400$

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(B) Let $H$ be the set of students who failed in History and $G$ be the set of students who failed in Geography.Given: $n(H) = 30 \%$,$n(G) = 35 \%$,and $n(H \cap G) = 27 \%$.Percentage of students who failed in at least one subject is given by the formula:$n(H \cup G) = n(H) + n(G) - n(H \cap G)$$n(H \cup G) = 30 \% + 35 \% - 27 \% = 38 \%$.Percentage of students who passed the examination = $100 \% - n(H \cup G) = 100 \% - 38 \% = 62 \%$.Let the total number of students who appeared be $x$.Given that $62 \%$ of $x = 248$.$\frac{62}{100} 	imes x = 248$$x = \frac{248 	imes 100}{62} = 4 	imes 100 = 400$.Therefore,the total number of students who appeared in the examination is $400$.

In an examination,$30 \%$ and $35 \%$ students respectively failed in History and Geography while $27 \%$ students failed in both the subjects. If the number of students passing the examination is $248$,find the total number of students who appeared in the examination.

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