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(B) Let the number of selected candidates be $5x$ and the number of unselected candidates be $x$.Total candidates applied = $5x + x = 6x$.According to

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$2760$

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(B) Let the number of selected candidates be $5x$ and the number of unselected candidates be $x$.Total candidates applied = $5x + x = 6x$.According to the problem,if $100$ fewer candidates had applied,the total number of candidates would be $6x - 100$.If $20$ fewer candidates were selected,the number of selected candidates would be $5x - 20$.The number of unselected candidates would then be $(6x - 100) - (5x - 20) = x - 80$.The new ratio of selected to unselected candidates is $6:1$,so:$\frac{5x - 20}{x - 80} = \frac{6}{1}$$5x - 20 = 6(x - 80)$$5x - 20 = 6x - 480$$6x - 5x = 480 - 20$$x = 460$The total number of candidates who applied is $6x = 6 	imes 460 = 2760$.

In an army selection process,the ratio of selected to unselected candidates was $5:1$. If $100$ fewer candidates had applied and $20$ fewer had been selected,the ratio of selected to unselected candidates would have been $6:1$. How many candidates had applied for the process?

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