In an AC circuit,I = 5 sin left( 100t - frac{ | vedclass

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(D) The instantaneous current is $I = 5 \sin \left( 100t - \frac{\pi}{2} \right)$ and the instantaneous voltage is $V = 200 \sin 100t$.Comparing these

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(D) The instantaneous current is $I = 5 \sin \left( 100t - \frac{\pi}{2} ight)$ and the instantaneous voltage is $V = 200 \sin 100t$.Comparing these with the standard forms $I = I_0 \sin(\omega t + \phi_1)$ and $V = V_0 \sin(\omega t + \phi_2)$,we get the phase of current $\phi_1 = -\frac{\pi}{2}$ and the phase of voltage $\phi_2 = 0$.The phase difference $\phi = \phi_2 - \phi_1 = 0 - (- \frac{\pi}{2}) = \frac{\pi}{2}$.The average power consumed in an $AC$ circuit is given by $P = V_{rms} I_{rms} \cos \phi$.Since $\phi = \frac{\pi}{2}$,the power factor $\cos \phi = \cos \left( \frac{\pi}{2} ight) = 0$.Therefore,the power consumed $P = V_{rms} I_{rms} 	imes 0 = 0$.

In an $AC$ circuit,$I = 5 \sin \left( 100t - \frac{\pi}{2} \right)$ and $V = 200 \sin 100t$. The power consumed is

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