In acidic medium,H_2O_2 changes Cr_2O_7^{2-} | vedclass

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(C) When $H_2O_2$ is added to an acidified solution of a dichromate $Cr_2O_7^{2-}$,a deep blue coloured complex,chromic peroxide $CrO_5$ (or $CrO(O_2)

Vedclass · Accepted Answer

$+6$

Vedclass · Answer

(C) When $H_2O_2$ is added to an acidified solution of a dichromate $Cr_2O_7^{2-}$,a deep blue coloured complex,chromic peroxide $CrO_5$ (or $CrO(O_2)_2$) is formed.$Cr_2O_7^{2-} + 2H^{+} + 4H_2O_2 \rightarrow 2CrO(O_2)_2 + 5H_2O$This deep blue coloured complex has a butterfly structure with two peroxide linkages $(-O-O-)$ and one double-bonded oxygen.Let the oxidation state of $Cr$ be $x$.In $CrO_5$,there is one oxygen atom with oxidation state $-2$ and four oxygen atoms in two peroxide linkages with oxidation state $-1$ each.Thus,$x + 1(-2) + 4(-1) = 0$.$x - 2 - 4 = 0$.$x = +6$.

In acidic medium,$H_2O_2$ changes $Cr_2O_7^{2-}$ to $CrO_5$ which has two $(-O-O-)$ bonds. Oxidation state of $Cr$ in $CrO_5$ is

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