In the above reaction,which of the following | vedclass

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(A) The starting material is $2,7$-dimethylanthraquinone. It is a symmetric molecule with two equivalent carbonyl groups at the $9$ and $10$ positions

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(A) The starting material is $2,7$-dimethylanthraquinone. It is a symmetric molecule with two equivalent carbonyl groups at the $9$ and $10$ positions. When $1$ equivalent of $MeMgBr$ (a Grignard reagent) is added,it performs a nucleophilic addition to one of the carbonyl groups. Since both carbonyl groups are equivalent,the attack can occur at either position,leading to the same product structure. The reaction involves the addition of a methyl group to the carbonyl carbon,followed by protonation during the aqueous workup $(H_2O)$ to form a tertiary alcohol. The resulting product is $2,7$-dimethyl$-9-$hydroxy$-9-$methylanthracen-$10$(9H)-one (or its equivalent at the $10$ position). Options $A$ and $B$ represent the same molecule due to the symmetry of the starting material. However,standard nomenclature usually assigns the lower number to the substituted position. Thus,the product is $2,7$-dimethyl$-9-$hydroxy$-9-$methylanthracen-$10$(9H)-one.

In the above reaction,which of the following will be obtained in maximum yield?

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