In a town with a population of 5000,3200 peop | vedclass

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(B) Let $E$ be the set of people who are egg-eaters and $M$ be the set of people who are meat-eaters.We are given:$n(U) = 5000$ (Total population)$n(E

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$800$

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(B) Let $E$ be the set of people who are egg-eaters and $M$ be the set of people who are meat-eaters.We are given:$n(U) = 5000$ (Total population)$n(E) = 3200$$n(M) = 2500$$n(E \cap M) = 1500$Using the formula for the union of two sets:$n(E \cup M) = n(E) + n(M) - n(E \cap M)$$n(E \cup M) = 3200 + 2500 - 1500$$n(E \cup M) = 5700 - 1500 = 4200$This represents the number of people who eat either egg or meat or both.The number of pure vegetarians is the total population minus those who eat egg or meat:$	ext{Pure vegetarians} = n(U) - n(E \cup M)$$= 5000 - 4200 = 800$

In a town with a population of $5000$,$3200$ people are egg-eaters,$2500$ are meat-eaters,and $1500$ eat both egg and meat. How many are pure vegetarians?

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