In a thermodynamic process,the pressure of a | vedclass

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(C) According to the first law of thermodynamics: $\Delta Q = \Delta U + \Delta W$.Here,the gas releases heat,so $\Delta Q = -30 \ J$.Work is done on

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(C) According to the first law of thermodynamics: $\Delta Q = \Delta U + \Delta W$.Here,the gas releases heat,so $\Delta Q = -30 \ J$.Work is done on the gas,so $\Delta W = -10 \ J$.Let the initial internal energy be $U_i = 30 \ J$ and the final internal energy be $U_f$.Then,$\Delta U = U_f - U_i = U_f - 30$.Substituting these values into the equation: $-30 = (U_f - 30) + (-10)$.$-30 = U_f - 30 - 10$.$-30 = U_f - 40$.$U_f = 40 - 30 = 10 \ J$.

In a thermodynamic process,the pressure of a fixed mass of a gas is changed in such a manner that the gas releases $30 \ J$ of heat and $10 \ J$ of work is done on the gas. If the initial internal energy of the gas was $30 \ J$,then the final internal energy will be ........ $J$.

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