In a single throw of 3 dice,find the probabil | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The total number of possible outcomes when throwing $3$ dice is $6 	imes 6 	imes 6 = 216$.We need to find the number of outcomes where the sum o

Vedclass · Accepted Answer

$\frac{1}{36}$

Vedclass · Answer

(C) The total number of possible outcomes when throwing $3$ dice is $6 	imes 6 	imes 6 = 216$.We need to find the number of outcomes where the sum of the numbers on the $3$ dice is $5$.The possible combinations are:$(1, 1, 3)$ which can be arranged in $3$ ways: $(1, 1, 3), (1, 3, 1), (3, 1, 1)$.$(1, 2, 2)$ which can be arranged in $3$ ways: $(1, 2, 2), (2, 1, 2), (2, 2, 1)$.Total favorable outcomes $= 3 + 3 = 6$.Therefore,the probability $P = \frac{	ext{Number of favorable outcomes}}{	ext{Total number of outcomes}} = \frac{6}{216} = \frac{1}{36}$.

In a single throw of $3$ dice,find the probability of getting a total of $5$.

Similar Questions

Three mangoes and three apples are in a box. If two fruits are chosen at random,the probability that one is a mango and the other is an apple is

$A$ bag contains tickets numbered from $1$ to $20$. Two tickets are drawn. The probability that both the numbers are prime,is

Two friends $A$ and $B$ have an equal number of daughters. There are three cinema tickets which are to be distributed among the daughters of $A$ and $B$. The probability that all the tickets go to the daughters of $A$ is $1/20$. The number of daughters each of them has is:

An urn contains $25$ balls numbered $1$ to $25$. Suppose an odd number is considered a 'success'. $2$ balls are drawn from the urn with replacement. Find the probability of getting no success.

If $P(A) = \frac{1}{2}$,$P(B) = \frac{1}{3}$ and $P(A \cap B) = \frac{1}{4}$,then $P(B/A) = $

Vedclass Test Series

Exam Paper Generator

Online Exam Module