In a single throw of 2 dice,find the probabil | vedclass

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(C) When $2$ dice are thrown,the total number of possible outcomes is $6 	imes 6 = 36$.Let $E$ be the event of getting a total of $3$ or $5$.The outc

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$\frac{1}{6}$

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(C) When $2$ dice are thrown,the total number of possible outcomes is $6 	imes 6 = 36$.Let $E$ be the event of getting a total of $3$ or $5$.The outcomes resulting in a total of $3$ are: $(1, 2)$ and $(2, 1)$.The outcomes resulting in a total of $5$ are: $(1, 4), (2, 3), (3, 2),$ and $(4, 1)$.Total favorable outcomes $= 2 + 4 = 6$.Probability $P(E) = \frac{	ext{Number of favorable outcomes}}{	ext{Total number of outcomes}} = \frac{6}{36} = \frac{1}{6}$.

In a single throw of $2$ dice,find the probability of getting a total of $3$ or $5$.

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