In a single slit diffraction experiment,the w | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) In a single slit diffraction experiment,the angular width of the central maximum is given by $	heta = \frac{2\lambda}{a}$,where $a$ is the slit w

Vedclass · Accepted Answer

The intensity increases by a factor of $4$ and the angular width decreases by a factor of $\frac{1}{2}$.

Vedclass · Answer

(D) In a single slit diffraction experiment,the angular width of the central maximum is given by $	heta = \frac{2\lambda}{a}$,where $a$ is the slit width. If the slit width $a$ is doubled $(a' = 2a)$,the new angular width becomes $	heta' = \frac{2\lambda}{2a} = \frac{	heta}{2}$. Thus,the angular width is halved.Regarding intensity,the intensity of the central maximum is proportional to the square of the slit width $(I \propto a^2)$. If the slit width is doubled,the new intensity $I'$ becomes $I' \propto (2a)^2 = 4a^2 = 4I$. Therefore,the intensity increases by a factor of $4$.

In a single slit diffraction experiment,the width of the slit is doubled. Which one of the following statements is correct?

Similar Questions

The Fraunhofer diffraction pattern of a single slit is formed in the focal plane of a lens of focal length $1\,m$. The width of the slit is $0.3\,mm$. If the third minimum is formed at a distance of $5\,mm$ from the central maximum, then the wavelength of light will be......$\mathring{A}$

Write the thoughts expressed by Richard Feynman regarding the difference between interference and diffraction.

$A$ slit of width $d$ is illuminated by white light. The first minimum for red light $(\lambda = 6500\,\mathring{A})$ will fall at $\theta = 30^\circ$ when $d$ will be

The angular spread of the central maximum in a diffraction pattern does not depend on . . . . . . .

Vedclass Test Series

Exam Paper Generator

Online Exam Module