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(A) The magnifying power $(M)$ of a simple microscope is given by the formula $M = \frac{D}{v}$,where $D$ is the least distance of distinct vision $(2

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$\frac{25}{f}$

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(A) The magnifying power $(M)$ of a simple microscope is given by the formula $M = \frac{D}{v}$,where $D$ is the least distance of distinct vision $(25 \ cm)$ and $v$ is the image distance.For a simple microscope,the magnifying power is defined as $M = 1 + \frac{D}{f}$ when the image is formed at the near point $(v = D)$.When the final image is formed at infinity,the object must be placed at the principal focus of the lens $(u = f)$.In this case,the magnifying power is given by $M = \frac{D}{f}$.Substituting $D = 25 \ cm$,we get $M = \frac{25}{f}$.

In a simple microscope,if the final image is located at infinity,then its magnifying power is:

Similar Questions

$A$ compound microscope consists of an eyepiece of focal length $6.25 \, cm$ and an objective lens of focal length $2.0 \, cm$,separated by a distance of $15 \, cm$. What is the magnifying power when the final image is formed at infinity?

Write the equation of magnification for a simple microscope when the image is formed at the near point.

The objective lens of a compound microscope produces a magnification of $10$. In order to get an overall magnification of $100$ when the image is formed at $25 \, cm$ from the eye,the focal length of the eye lens should be:

The intermediate image formed by the objective of a compound microscope is

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