In a $\sigma$ bond,
- ASidewise as well as end to end overlap of orbitals take place
- BSidewise overlap of orbitals takes place
- CEnd to end overlap of orbitals takes place
- DNone of the above
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The ratio of the number of $\sigma$ and $\pi$ bonds in benzene is equal to:
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$(a)$ $HC \equiv C-CH=CH-CH_3$
$(b)$ $CH_2=C=CH-CH_3$
$(a)$ $HC \equiv C-CH=CH-CH_3$
$(b)$ $CH_2=C=CH-CH_3$
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