In a school,391 boys and 323 girls have been | vedclass

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(C) To find the largest possible number of students in each class such that the number of boys and girls in each class is equal,we need to calculate t

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$44$

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(C) To find the largest possible number of students in each class such that the number of boys and girls in each class is equal,we need to calculate the $H.C.F.$ of $391$ and $323$.First,find the prime factorization of $391$ and $323$:$391 = 17 	imes 23$$323 = 17 	imes 19$The $H.C.F.$ of $391$ and $323$ is $17$. This means each class contains $17$ students.Now,calculate the total number of classes:Number of boys' classes = $391 / 17 = 23$Number of girls' classes = $323 / 17 = 19$Total number of classes = $23 + 19 = 42$.

In a school,$391$ boys and $323$ girls have been divided into the largest possible equal classes,so that each class of boys numbers the same as each class of girls. What is the number of classes?

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