In a school,442 boys and 374 girls have been | vedclass

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(D) Number of boys $= 442$; Number of girls $= 374$.To find the largest possible equal number of students in each class,we calculate the $HCF$ of $442

Vedclass · Accepted Answer

$24$

Vedclass · Answer

(D) Number of boys $= 442$; Number of girls $= 374$.To find the largest possible equal number of students in each class,we calculate the $HCF$ of $442$ and $374$.Prime factorization of $442 = 2 	imes 13 	imes 17$.Prime factorization of $374 = 2 	imes 11 	imes 17$.$HCF(442, 374) = 2 	imes 17 = 34$.So,each class contains $34$ students.Number of classes of boys $= 442 \div 34 = 13$.Number of classes of girls $= 374 \div 34 = 11$.Total number of classes $= 13 + 11 = 24$.

In a school,$442$ boys and $374$ girls have been divided into the largest possible equal classes,so that each class of boys numbers the same as each class of girls. What is the number of classes?

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