In a regular octahedral molecule,$MX_6$,the number of $X-M-X$ bonds at $180^{\circ}$ is

Match the molecules in List-$I$ with their respective shapes in List-$II$.

List-$I$ (Molecule)	List-$II$ (Shape)
$A. SF_4$	$I. T\text{-shaped}$
$B. ClF_3$	$II. \text{Square planar}$
$C. BrF_5$	$III. \text{See-saw}$
$D. XeF_4$	$IV. \text{Square pyramidal}$

Which species is planar?

Given below are two statements:
Statement $I$: The number of compounds among $SO_2$,$SO_3$,$SF_4$,$SF_6$ and $H_2S$ in which sulphur does not obey the Octet rule is $3$.
Statement $II$: Among $[H_2O, ClF_3, SF_4]$,$[NH_3, BrF_5, SF_4]$,$[BrF_5, ClF_3, XeF_4]$ and $[XeF_4, ClF_3, H_2O]$,the number of sets in which all the molecules have one lone pair of electrons on the central atom is $1$.

The $H-O-H$ bond angle in a water molecule is about .............. $^\circ$.

Match the following molecules with their respective geometries and choose the correct code.

Molecule	Geometry
$(A)$ $XeF_2$	$1$. Trigonal pyramidal
$(B)$ $XeO_3$	$2$. Distorted octahedral
$(C)$ $XeF_6$	$3$. Linear
$(D)$ $XeOF_4$	$4$. Square pyramidal