In a reaction,$n_1 A + n_2 B \rightarrow m_1 C + m_2 D$,$5 \ M$ solution of reactant $A$ is allowed to react with $3 \ M$ solution of reactant $B$. After $5 \ s$,the concentration of $A$ was found to be $4 \ M$. The rate of decomposition of $A$ and the rate of formation of $D$ are respectively $:-$

  • A
    $0.2 \ M \ sec^{-1} ; \left(\frac{m_2}{m_1} \times 0.2\right) \ M \ sec^{-1}$
  • B
    $0.2 \ M \ sec^{-1} ; \left(\frac{n_2}{m_2} \times 0.2\right) \ M \ sec^{-1}$
  • C
    $0.1 \ M \ sec^{-1} ; \left(\frac{m_2}{n_1} \times 0.2\right) \ M \ sec^{-1}$
  • D
    $0.2 \ M \ sec^{-1} ; \left(\frac{m_2}{n_1} \times 0.2\right) \ M \ sec^{-1}$

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Fill in the blanks:
$(a)$ Catalyst ......... the rate of reaction.
$(b)$ Inhibitor ......... the rate of the reaction.
$(c)$ If temperature increases,the rate of reaction ......... .

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The decomposition of $N_{2}O_{5}$ in $CCl_{4}$ at $318 \ K$ has been studied by monitoring the concentration of $N_{2}O_{5}$ in the solution. Initially the concentration of $N_{2}O_{5}$ is $2.33 \ mol \ L^{-1}$ and after $184 \ minutes$,it is reduced to $2.08 \ mol \ L^{-1}$. The reaction takes place according to the equation:
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What is the average rate of reaction when the change in concentration of product is $0.05 \ M$ in $20 \ s$ (in $M \ s^{-1}$)?

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