In a primary coil,a 5,A current is flowing at | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) For an ideal transformer,the ratio of the secondary voltage $(V_s)$ to the primary voltage $(V_p)$ is equal to the ratio of the number of turns in

Vedclass · Accepted Answer

$10 : 1$

Vedclass · Answer

(B) For an ideal transformer,the ratio of the secondary voltage $(V_s)$ to the primary voltage $(V_p)$ is equal to the ratio of the number of turns in the secondary coil $(N_s)$ to the number of turns in the primary coil $(N_p)$.This is given by the transformer equation: $\frac{N_s}{N_p} = \frac{V_s}{V_p}$.Given: $V_p = 220\,V$ and $V_s = 2200\,V$.Substituting the values: $\frac{N_s}{N_p} = \frac{2200}{220} = \frac{10}{1}$.Therefore,the ratio of the number of turns in the secondary coil to the primary coil is $10 : 1$.

In a primary coil,a $5\,A$ current is flowing at $220\,V$. In the secondary coil,a voltage of $2200\,V$ is produced. The ratio of the number of turns in the secondary coil to the primary coil is:

Similar Questions

Due to which reasons do energy losses occur in an actual transformer?

The core of a transformer is made up of:

$A$ $100\%$ efficient transformer has $100$ turns in the primary and $25$ turns in its secondary coil. If the current in the secondary coil is $4 \text{ A}$, then the current in the primary coil is ... $ \text{A}$

$A$ step-down transformer is connected to a main supply of $200\,V$ to operate a $6\,V$,$30\,W$ bulb. The current in the primary coil is.....$A$

In a step-up transformer,the transformation ratio is $4:1$. If a Leclanche cell having an $EMF$ of $1.5 \ V$ is connected to the primary coil of the transformer,then the voltage obtained across its secondary coil is . . . . . . .

Vedclass Test Series

Exam Paper Generator

Online Exam Module