In a potentiometer experiment,the balancing l | vedclass

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(B) The internal resistance $r$ of a cell is given by the formula:$r = R \left[ \frac{l_1}{l_2} - 1 \right]$Where:$R = 2\,\Omega$ (external shunt resi

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$2$

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(B) The internal resistance $r$ of a cell is given by the formula:$r = R \left[ \frac{l_1}{l_2} - 1 ight]$Where:$R = 2\,\Omega$ (external shunt resistance)$l_1 = 240\,cm$ (balancing length without shunt)$l_2 = 120\,cm$ (balancing length with shunt)Substituting the values into the formula:$r = 2 \left[ \frac{240}{120} - 1 ight]$$r = 2 [2 - 1]$$r = 2 	imes 1 = 2\,\Omega$Thus,the internal resistance of the cell is $2\,\Omega$.

In a potentiometer experiment,the balancing length with a cell is $240\,cm$. On shunting the cell with a resistance of $2\,\Omega$,the balancing length becomes $120\,cm$. The internal resistance of the cell is ................... $\Omega$.

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