In a nuclide,one $a.m.u.$ of mass is dissipated into energy to bind its nucleons. The energy equivalent of this mass is

$_{90}Th^{228}$ emits four alpha and one beta particles. The number of neutrons in the daughter element is:

The nucleus $^{64}_{29}Cu$ accepts an orbital electron to yield:

The isotopic mass of ${}_{3}^{7}Li$ is $7.016005 \ u$ and those of the $H$ atom and neutron are respectively $1.007825 \ u$ and $1.008665 \ u$. Then,the binding energy of the ${}_{3}^{7}Li$ nucleus is: (in $MeV$)

If the mass defect of a nuclide is $3.32 \times 10^{-26} \ g$,its binding energy in $MeV$ is:

Match List-$I$ and List-$II$ and choose the correct option using the codes given below:

List-$I$ (Nuclear reactor component)	List-$II$ (Used substance)
$1$. Moderator	$(a)$ Uranium
$2$. Control rods	$(b)$ Graphite
$3$. Fuel rods	$(c)$ Boron
$4$. Coolant	$(d)$ Lead
	$(e)$ Sodium