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(B) The rate of mass consumption is given by $\frac{\Delta m}{\Delta t} = 1 	imes 10^{-3} 	ext{ g s}^{-1} = 10^{-6} 	ext{ kg s}^{-1}$.According to

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$9 	imes 10^7$

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(B) The rate of mass consumption is given by $\frac{\Delta m}{\Delta t} = 1 	imes 10^{-3} 	ext{ g s}^{-1} = 10^{-6} 	ext{ kg s}^{-1}$.According to Einstein's mass-energy equivalence principle,the power $P$ generated is given by $P = \frac{\Delta E}{\Delta t} = \left(\frac{\Delta m}{\Delta t}ight) c^2$.Substituting the values,where $c = 3 	imes 10^8 	ext{ m s}^{-1}$:$P = 10^{-6} 	ext{ kg s}^{-1} 	imes (3 	imes 10^8 	ext{ m s}^{-1})^2$.$P = 10^{-6} 	imes 9 	imes 10^{16} 	ext{ W}$.$P = 9 	imes 10^{10} 	ext{ W}$.Since $1 	ext{ kW} = 10^3 	ext{ W}$,we convert the power to kW:$P = \frac{9 	imes 10^{10}}{10^3} 	ext{ kW} = 9 	imes 10^7 	ext{ kW}$.

In a nuclear reactor,the fuel is consumed at the rate of $1 \times 10^{-3} \text{ g s}^{-1}$. The power generated in kW is

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