In a nuclear fission process,a high mass nucl | vedclass

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(A) The energy released $(Q)$ in a nuclear fission process is given by the difference between the total binding energy of the products and the total b

Vedclass · Accepted Answer

$236$

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(A) The energy released $(Q)$ in a nuclear fission process is given by the difference between the total binding energy of the products and the total binding energy of the reactants.$Q = BE_{	ext{products}} - BE_{	ext{reactants}}$Given:Mass number of reactant $(A_R)$ = $236$Binding energy per nucleon of reactant $(BE_{R})$ = $7.6 \ MeV/	ext{nucleon}$Total binding energy of reactant = $236 	imes 7.6 \ MeV = 1793.6 \ MeV$Mass number of each product $(A_P)$ = $118$Binding energy per nucleon of product $(BE_{P})$ = $8.6 \ MeV/	ext{nucleon}$Total binding energy of two products = $2 	imes (118 	imes 8.6) \ MeV = 236 	imes 8.6 \ MeV = 2029.6 \ MeV$Energy released $(Q)$ = $2029.6 \ MeV - 1793.6 \ MeV = 236 \ MeV$.

In a nuclear fission process,a high mass nuclide $(A \approx 236)$ with binding energy $7.6 \ MeV/\text{nucleon}$ dissociates into two middle mass nuclides $(A \approx 118)$,each having a binding energy of $8.6 \ MeV/\text{nucleon}$. The energy released in the process is $MeV$.

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