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(B) For a moderately asymmetrical distribution,the empirical relationship between mean,median,and mode is given by:$	ext{Mode} = 3 	imes 	ext{Media

Vedclass · Accepted Answer

$5$

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(B) For a moderately asymmetrical distribution,the empirical relationship between mean,median,and mode is given by:$	ext{Mode} = 3 	imes 	ext{Median} - 2 	imes 	ext{Mean}$Given:$	ext{Mode} = 7$$	ext{Mean} = 4$Substituting the values into the formula:$7 = 3 	imes 	ext{Median} - 2 	imes 4$$7 = 3 	imes 	ext{Median} - 8$$7 + 8 = 3 	imes 	ext{Median}$$15 = 3 	imes 	ext{Median}$$	ext{Median} = \frac{15}{3} = 5$Therefore,the median is $5$.

Class	$0-5$	$5-10$	$10-15$	$15-20$	$20-25$	$25-30$
Frequency $(f_i)$	$3$	$4$	$7$	$11$	$2$	$5$

In a moderately asymmetrical distribution,the mode and mean are $7$ and $4$ respectively. The median is:

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Class $0-5$ $5-10$ $10-15$ $15-20$ $20-25$ $25-30$

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