In a hydrogen-oxygen fuel cell,the combustion of hydrogen occurs to:

  • A
    Produce high purity water
  • B
    Create potential difference between the two electrodes
  • C
    Generate heat
  • D
    Remove adsorbed oxygen from electrode surfaces

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$A$ galvanic cell has an electrical potential of $1.1 \ V$. If an opposing potential of $1.1 \ V$ is applied to this cell,what will happen to the cell reaction and the current flowing through the cell?

Why is a finely divided particle layer of $Pt$ and $Pd$ provided on the electrodes of a fuel cell?

Match List-$I$ with List-$II$.
$LIST$-$I$ (Cell) $LIST$-$II$ (Use/Property/Reaction)
$A$. Leclanche cell $I$. Converts energy of combustion into electrical energy
$B$. Ni-Cd cell $II$. Does not involve any ion in solution and is used in hearing aids
$C$. Fuel cell $III$. Rechargeable
$D$. Mercury cell $IV$. Reaction at anode $Zn \rightarrow Zn^{2+} + 2e^-$

Choose the correct answer from the options given below:

The limiting molar conductivity $\Lambda^o$ for $NaCl$,$KBr$ and $KCl$ are $126$,$152$ and $150 \ S \ cm^2 \ mol^{-1}$ respectively. The $\Lambda^o$ for $NaBr$ is (in $S \ cm^2 \ mol^{-1}$).

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