(A) The atomic mass of $H = 1 \ g/mol$ and $C = 12 \ g/mol$. Given the mass ratio of $H : C = 1 : 3$. To find the mole ratio,divide the mass by the re

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(A) The atomic mass of $H = 1 \ g/mol$ and $C = 12 \ g/mol$. Given the mass ratio of $H : C = 1 : 3$. To find the mole ratio,divide the mass by the respective atomic mass: Moles of $H = 1 / 1 = 1$. Moles of $C = 3 / 12 = 0.25$. Now,find the simplest molar ratio: $H : C = 1 : 0.25 = 4 : 1$. Therefore,for every $1$ atom of $C$,there are $4$ atoms of $H$. Hence,the empirical formula is $CH_4$.

Class 11 Chemistry Some Basic Concepts of Chemistry Percentage composition and Molecular formula

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In a hydrocarbon,the mass ratio of hydrogen and carbon is $1 : 3$. The empirical formula of the hydrocarbon is

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A
$CH_4$
B
$CH_2$
C
$C_2H$
D
$CH_3$

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Percentage composition and Molecular formula

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In a hydrocarbon,the mass ratio of hydrogen and carbon is $1 : 3$. The empirical formula of the hydrocarbon is

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