In a group of six women,there are four table | vedclass

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(A) Let the six women be $A$ (Amala),$K$ (Kamala),$Ko$ (Komala),$N$ (Nirmala),$V$ (Vimala),and $S$ (Shyamala).$1$. Total women = $6$.$2$. Table Tennis

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Nirmala

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(A) Let the six women be $A$ (Amala),$K$ (Kamala),$Ko$ (Komala),$N$ (Nirmala),$V$ (Vimala),and $S$ (Shyamala).$1$. Total women = $6$.$2$. Table Tennis $(TT)$ players = $4$.$3$. Postgraduates in Economics $(PE)$ = $4$.$4$. Postgraduate in Commerce $(PC)$ = $1$ $(S)$.$5$. Bank Employees $(BE)$ = $3$.Given:- $V, K$ are $BE$.- $A, Ko$ are unemployed (not $BE$).- $Ko, N$ are $TT$.- $A, K, Ko, N$ are $PE$.- $S$ is $PC$.Since there are $3$ $BE$ and we know $V, K$ are $BE$,the third $BE$ must be one of the remaining $(A, Ko, N, S)$.- $A$ and $Ko$ are unemployed,so they are not $BE$.- $S$ is $PC$,and the $PE$ group has $4$ members $(A, K, Ko, N)$. Two of these $PE$ are $BE$. Since $K$ is $BE$,one of $(A, Ko, N)$ must be the other $BE$.- Since $A$ and $Ko$ are unemployed,$N$ must be the third $BE$.- Now,$N$ is both a $TT$ player (given) and a $BE$ (derived). Thus,$N$ satisfies both conditions.

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