In a galvanometer,$5 \%$ of the total current in the circuit passes through it. If the resistance of the galvanometer is $G$,the shunt resistance $S$ connected to the galvanometer is

  • A
    $19 G$
  • B
    $\frac{G}{19}$
  • C
    $20 G$
  • D
    $\frac{G}{20}$

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