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(C) The formula for fringe width $(\beta)$ in a Young's double slit experiment is given by $\beta = \frac{D \lambda}{d}$,where $D$ is the distance bet

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becomes $\frac{1}{20}$ times.

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(C) The formula for fringe width $(\beta)$ in a Young's double slit experiment is given by $\beta = \frac{D \lambda}{d}$,where $D$ is the distance between the slits and the screen,$\lambda$ is the wavelength of light,and $d$ is the distance between the slits.Given that the new distance between slits $d' = 10d$ and the new distance from the screen $D' = \frac{D}{2}$.The new fringe width $\beta'$ is given by $\beta' = \frac{D' \lambda}{d'} = \frac{(\frac{D}{2}) \lambda}{10d} = \frac{D \lambda}{20d}$.Since $\beta = \frac{D \lambda}{d}$,we have $\beta' = \frac{\beta}{20}$.Thus,the fringe width becomes $\frac{1}{20}$ times the original fringe width.

In a double slit experiment,the distance between slits is increased $10$ times,whereas their distance from the screen is halved. The fringe width:

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