In a double-slit experiment,the angular width | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The angular width of a fringe in a double-slit experiment is given by $	heta = \frac{\lambda}{d}$,where $\lambda$ is the wavelength of light and

Vedclass · Accepted Answer

$0.15$

Vedclass · Answer

(A) The angular width of a fringe in a double-slit experiment is given by $	heta = \frac{\lambda}{d}$,where $\lambda$ is the wavelength of light and $d$ is the slit separation.When the apparatus is immersed in a medium of refractive index $\mu$,the wavelength of light changes to $\lambda' = \frac{\lambda}{\mu}$.Consequently,the new angular width $	heta'$ becomes $	heta' = \frac{\lambda'}{d} = \frac{\lambda}{\mu d} = \frac{	heta}{\mu}$.Given $	heta = 0.2^{\circ}$ and $\mu = 4/3$,the new angular width is:$	heta' = \frac{0.2^{\circ}}{4/3} = 0.2^{\circ} 	imes \frac{3}{4} = 0.15^{\circ}$.Thus,the angular width of the fringe in water is $0.15^{\circ}$.

Similar Questions

In Young's double-slit experiment,the fringe width will remain the same if:

In Young's double slit experiment,the angular width of fringes is $0.20^o$ for sodium light of wavelength $5890 \ \mathring A$. If the complete system is dipped in water,then the angular width of the fringes becomes....$^o$

In Young's double-slit experiment, light of wavelength $4000 \, Å$ is used to produce bright fringes of width $0.6 \, mm$ at a distance of $2 \, m$ from the slits. If the whole apparatus is immersed in a liquid of refractive index $1.5$, what will be the new fringe width in $mm$?

In a Young's double-slit experiment,the wavelength of light used is $6000 \, \mathring A$. The phase difference between the central bright fringe and the third bright fringe is .......

Vedclass Test Series

Exam Paper Generator

Online Exam Module