In a dihybrid Mendelian cross,how many types | vedclass

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(C) In a dihybrid cross,two pairs of contrasting traits are considered.For a dihybrid cross,the number of phenotypes is calculated by the formula $2^n

Vedclass · Accepted Answer

$9$ and $4$ respectively

Vedclass · Answer

(C) In a dihybrid cross,two pairs of contrasting traits are considered.For a dihybrid cross,the number of phenotypes is calculated by the formula $2^n$,where $n$ is the number of gene pairs. Here,$n = 2$,so phenotypes = $2^2 = 4$.The number of genotypes is calculated by the formula $3^n$. Here,$n = 2$,so genotypes = $3^2 = 9$.Therefore,in a dihybrid Mendelian cross,there are $9$ types of genotypes and $4$ types of phenotypes.

In a dihybrid Mendelian cross,how many types of genotype and phenotype will be obtained $:-$

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