Difficult
In a cylindrical container open to the atmosphere from the top,a liquid is filled up to a $10\, m$ depth. The density of the liquid varies with depth $h$ from the surface as $\rho(h) = 100 + 6h^2$,where $h$ is in meters and $\rho$ is in $kg/m^3$. The pressure at the bottom of the container will be: (Atmospheric pressure $P_0 = 10^5\, Pa$,$g = 10\, m/s^2$)
- A$1.7 \times 10^5\, Pa$
- B$1.4 \times 10^5\, Pa$
- C$1.6 \times 10^5\, Pa$
- D$1.3 \times 10^5\, Pa$
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