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(A) The average kinetic energy per molecule of an ideal gas is given by the formula $K_{avg} = \frac{3}{2} k_{B} T$,where $k_{B}$ is the Boltzmann con

Vedclass · Accepted Answer

Yes,they will have the same average kinetic energy per molecule.

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(A) The average kinetic energy per molecule of an ideal gas is given by the formula $K_{avg} = \frac{3}{2} k_{B} T$,where $k_{B}$ is the Boltzmann constant and $T$ is the absolute temperature of the gas.Since both gases are in the same container,they are in thermal equilibrium and must be at the same temperature $T$.Because the average kinetic energy depends only on the temperature $T$ and not on the mass or nature of the gas molecules,both gases will have the same average kinetic energy per molecule.

In a container,there is a mixture of two different gases. Will both gases have the same kinetic energy?

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