In a communication system operating at a wavelength of $800 \,nm$, only $1 \%$ of the source frequency is available as signal bandwidth. The number of channels accommodated for transmitting $TV$ signals of bandwidth $6 \,MHz$ is

  • A
    $\frac{1}{25} \times 10^7$
  • B
    $\frac{1}{21} \times 10^7$
  • C
    $\frac{1}{16} \times 10^7$
  • D
    $\frac{1}{12} \times 10^7$

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